Analisis Regresi 3

Nama :Dhika Mulyasari
Nim : 20160302251

Latihan 55

no	berat badan (Y)	tinggi badan (X)
	(kg)	(cm)
1	54	155	-7.55	-7.7	58.135	59.29
2	51	155	-10.55	-7.7	81.235	59.29
3	53	156	-8.55	-6.7	57.285	44.89
4	57	157	-4.55	-5.7	25.935	32.49
5	52	159	-9.55	-3.7	35.335	13.69
6	61	159	-0.55	-3.7	2.035	13.69
7	60	160	-1.55	-2.7	4.185	7.29
8	64	160	2.45	-2.7	-6.615	7.29
9	58	161	-3.55	-1.7	6.035	2.89
10	63	162	1.45	-0.7	-1.015	0.49
11	77	172	15.45	9.3	143.685	86.49
12	71	170	9.45	7.3	68.985	53.29
13	68	168	6.45	5.3	34.185	28.09
14	64	166	2.45	3.3	8.085	10.89
15	63	164	1.45	1.3	1.885	1.69
16	68	167	6.45	4.3	27.735	18.49
17	70	168	8.45	5.3	44.785	28.09
18	63	166	1.45	3.3	4.785	10.89
19	59	165	-2.55	2.3	-5.865	5.29
20	55	164	-6.55	1.3	-8.515	1.69
jumlah	1231	3254			582.3	486.2
rata2	61.55	162.7
SD	6.954551709	5.058603926
	1.197655286
Nilai	-133.308515

maka persamaan regresi garis lurus adalah
 

ini berarti :
a. nilai rerata BB ketika TB = 0 adalah -133.309
b. setiap kenaikan TB sebesar 1 cm maka akan terjadi kenaikan BB sebesar 1.19 kg
c. misalkan, seorang anak TB 160 cm, maka prediksi BB adalah
= -133.309 + (1.198*160)
= 58.371

Pertanyaan :
berapakah BB anak bila tingginya :
a. 150 cm? Y= -133.309 + (1.198*150) = 46.34
b. 155 cm? Y= -133.309 + (1.198*155) = 52.33
c. 165 cm? Y= -133.309 + (1.198*165) = 64.3 

Latihan 57

1. Data Indeks MassaTubuh (IMT) dan Glukosa post prandial (GPP)
 

Kasus	IMT	GPP	Y-y	X-x	(Y-y)(X-x)	(X-x)2
1	18.6	150	-3.003703704	7.962962963	-23.91838134	63.40877915
2	28.1	150	6.496296296	7.962962963	51.7297668	63.40877915
3	25.1	120	3.496296296	-22.03703704	-77.04801097	485.6310014
4	21.6	150	-0.003703704	7.962962963	-0.029492455	63.40877915
5	28.4	190	6.796296296	47.96296296	325.9705075	2300.445816
6	20.8	110	-0.803703704	-32.03703704	25.74828532	1026.371742
7	23.2	150	1.596296296	7.962962963	12.71124829	63.40877915
8	15.9	130	-5.703703704	-12.03703704	68.65569273	144.8902606
9	16.4	130	-5.203703704	-12.03703704	62.63717421	144.8902606
10	18.2	120	-3.403703704	-22.03703704	75.00754458	485.6310014
11	17.9	130	-3.703703704	-12.03703704	44.58161866	144.8902606
12	21.8	140	0.196296296	-2.037037037	-0.399862826	4.14951989
13	16.1	100	-5.503703704	-42.03703704	231.3593964	1767.112483
14	21.5	150	-0.103703704	7.962962963	-0.825788752	63.40877915
15	24.5	130	2.896296296	-12.03703704	-34.86282579	144.8902606
16	23.7	180	2.096296296	37.96296296	79.58161866	1441.186557
17	21.9	140	0.296296296	-2.037037037	-0.603566529	4.14951989
18	18.6	135	-3.003703704	-7.037037037	21.13717421	49.51989026
19	27	140	5.396296296	-2.037037037	-10.99245542	4.14951989
20	18.9	100	-2.703703704	-42.03703704	113.6556927	1767.112483
21	16.7	100	-4.903703704	-42.03703704	206.1371742	1767.112483
22	18.5	170	-3.103703704	27.96296296	-86.78875171	781.9272977
23	19.4	150	-2.203703704	7.962962963	-17.54801097	63.40877915
24	24	160	2.396296296	17.96296296	43.04458162	322.6680384
25	26.8	200	5.196296296	57.96296296	301.1927298	3359.705075
26	28.7	190	7.096296296	47.96296296	340.3593964	2300.445816
27	21	120	-0.603703704	-22.03703704	13.30384088	485.6310014
Jumlah	583.3	3835			1763.796296	19312.96296
Rerata	21.6037037	142.037037
SD	3.963339839	27.25447244
B1	0.091327069
B0	8.631877457
Maka, persamaan regresi garis lurus adalah
Y= B0-B1X
Y= 8.63 - 0.09 X

2. Data Indeks Massa Tubuh (IMT) dan Trigliserida

Kasus	IMT	TRIG	Y-y	X-x	(Y-y)(X-x)	(X-x)2
1	18.6	180	-3.003703704	6.481481481	-19.46844993	42.00960219
2	28.1	180	6.496296296	6.481481481	42.10562414	42.00960219
3	25.1	160	3.496296296	-13.51851852	-47.26474623	182.7503429
4	21.6	180	-0.003703704	6.481481481	-0.024005487	42.00960219
5	28.4	210	6.796296296	36.48148148	247.9389575	1330.898491
6	20.8	140	-0.803703704	-33.51851852	26.93895748	1123.491084
7	23.2	180	1.596296296	6.481481481	10.34636488	42.00960219
8	15.9	160	-5.703703704	-13.51851852	77.10562414	182.7503429
9	16.4	160	-5.203703704	-13.51851852	70.34636488	182.7503429
10	18.2	150	-3.403703704	-23.51851852	80.05006859	553.1207133
11	17.9	160	-3.703703704	-13.51851852	50.06858711	182.7503429
12	21.8	170	0.196296296	-3.518518519	-0.690672154	12.37997257
13	16.1	130	-5.503703704	-43.51851852	239.5130316	1893.861454
14	21.5	180	-0.103703704	6.481481481	-0.672153635	42.00960219
15	24.5	160	2.896296296	-13.51851852	-39.15363512	182.7503429
16	23.7	210	2.096296296	36.48148148	76.47599451	1330.898491
17	21.9	170	0.296296296	-3.518518519	-1.042524005	12.37997257
18	18.6	165	-3.003703704	-8.518518519	25.58710562	72.56515775
19	27	170	5.396296296	-3.518518519	-18.98696845	12.37997257
20	18.9	140	-2.703703704	-33.51851852	90.62414266	1123.491084
21	16.7	130	-4.903703704	-43.51851852	213.4019204	1893.861454
22	18.5	200	-3.103703704	26.48148148	-82.19067215	701.2688615
23	19.4	180	-2.203703704	6.481481481	-14.28326475	42.00960219
24	24	190	2.396296296	16.48148148	39.49451303	271.6392318
25	26.8	230	5.196296296	56.48148148	293.494513	3190.15775
26	28.7	240	7.096296296	66.48148148	471.7722908	4419.78738
27	21	160	-0.603703704	-13.51851852	8.161179698	182.7503429
Jumlah	583.3	4685			1839.648148	19290.74074
Rerata	21.6037	173.5185
SD	3.96334	27.23879
B1	0.095364
B0	5.05623
Maka, persamaan regresi garis lurus adalah
Y= B0-B1X
Y= 5.05 - 0.09 X